java.lang
Class Double
java.lang.Object
java.lang.Double
public final class Double
- extends Object
The Double class wraps a value of the primitive type double in an object.
An object of type Double contains a single field whose type is double.
In addition, this class provides several methods for converting a double to a
String and a String to a double, as well as other constants and methods useful
when dealing with a double.
|
Field Summary |
static double |
MAX_VALUE
The largest positive finite value of type double. |
static double |
MIN_VALUE
The smallest positive value of type double. |
static double |
NaN
A Not-a-Number (NaN) value of type double. |
static double |
NEGATIVE_INFINITY
The negative infinity of type double. |
static double |
POSITIVE_INFINITY
The positive infinity of type double. |
(package private) static int |
strSize
Creates a string representation of the double argument. |
|
Constructor Summary |
Double(double value)
Constructs a newly allocated Double object that represents
the primitive double argument. |
|
Method Summary |
static long |
doubleToLongBits(double value)
Returns a representation of the specified floating-point value according to the
IEEE 754 floating-point "double format" bit layout. |
double |
doubleValue()
Returns the double value of this Double. |
boolean |
equals(Object obj)
Compares this object against the specified object. |
float |
floatValue()
Returns the float value of this Double. |
int |
hashCode()
Returns a hashcode for this Double object. |
int |
intValue()
Returns the integer value of this Double (by casting to an int). |
boolean |
isInfinite()
Returns true if this Double value is infinitely large in magnitude. |
static boolean |
isInfinite(double v)
Returns true if this Double value is infinitely large in magnitude. |
boolean |
isNaN()
Returns true if this Double value is the special Not-a-Number (NaN) value. |
static boolean |
isNaN(double v)
Returns true if the specified number is the special Not-a-Number (NaN) value. |
static double |
longBitsToDouble(long bits)
Returns the double-float corresponding to a given bit representation. |
long |
longValue()
Returns the long value of this Double (by casting to a long). |
static double |
parseDouble(String s)
Returns a new double initialized to the value represented by the
specified String, as performed by the valueOf method of class Double. |
short |
shortValue()
Returns the value of this Double as a short (by casting to a short). |
String |
toString()
Returns a String representation of this Double object. |
static String |
toString(double f)
Creates a string representation of the double argument. |
static Double |
valueOf(String s)
Returns a new Double object initialized to the value represented by the specified string. |
POSITIVE_INFINITY
public static final double POSITIVE_INFINITY
- The positive infinity of type double. It is equal to the value returned by
Double.longBitsToDouble(0x7ff0000000000000L).
- See Also:
- Constant Field Values
NEGATIVE_INFINITY
public static final double NEGATIVE_INFINITY
- The negative infinity of type double. It is equal to the value returned by
Double.longBitsToDouble(0xfff0000000000000L).
- See Also:
- Constant Field Values
NaN
public static final double NaN
- A Not-a-Number (NaN) value of type double. It is equal to the value returned by
Double.longBitsToDouble(0x7ff8000000000000L).
- See Also:
- Constant Field Values
MAX_VALUE
public static final double MAX_VALUE
- The largest positive finite value of type double. It is equal to the value returned by
Double.longBitsToDouble(0x7fefffffffffffffL)
- See Also:
- Constant Field Values
MIN_VALUE
public static final double MIN_VALUE
- The smallest positive value of type double. It is equal to the value returned by
Double.longBitsToDouble(0x1L).
- See Also:
- Constant Field Values
strSize
static final int strSize
- Creates a string representation of the double argument. All characters mentioned below are ASCII characters.
If the argument is NaN, the result is the string "NaN".
Otherwise, the result is a string that represents the sign and magnitude (absolute value) of the argument.
If the sign is negative, the first character of the result is '-' ('-'); if the sign is positive, no sign character
appears in the result. As for the magnitude m:
If m is infinity, it is represented by the characters "Infinity"; thus, positive infinity produces the result "Infinity"
and negative infinity produces the result "-Infinity".
If m is zero, it is represented by the characters "0.0"; thus, negative zero produces the result "-0.0" and
positive zero produces the result "0.0".
If m is greater than or equal to 10-3 but less than 107, then it is represented as the integer part of m,
in decimal form with no leading zeroes, followed by '.' (.), followed by one or more decimal digits
representing the fractional part of m.
If m is less than 10-3 or not less than 107, then it is represented in so-called "computerized scientific
notation." Let n be the unique integer such that 10n<=m<10n+1; then let a be the mathematically
exact quotient of m and 10n so that 1<=a<10. The magnitude is then represented as the integer
part of a, as a single decimal digit, followed by '.' (.), followed by decimal digits representing the
fractional part of a, followed by the letter 'E' (E), followed by a representation of n as a decimal integer,
as produced by the method Integer.toString(int).
How many digits must be printed for the fractional part of m or a? There must be at least one
digit to represent the fractional part, and beyond that as many, but only as many, more digits as are
needed to uniquely distinguish the argument value from adjacent values of type double. That is,
suppose that x is the exact mathematical value represented by the decimal representation
produced by this method for a finite nonzero argument d. Then d must be the double value nearest to x;
or if two double values are equally close to x, then d must be one of them and the least significant bit
of the significand of d must be 0.
- See Also:
- Constant Field Values
Double
public Double(double value)
- Constructs a newly allocated Double object that represents
the primitive double argument.
doubleToLongBits
public static long doubleToLongBits(double value)
- Returns a representation of the specified floating-point value according to the
IEEE 754 floating-point "double format" bit layout.
Bit 63 (the bit that is selected by the mask 0x8000000000000000L) represents the sign of
the floating-point number. Bits 62-52 (the bits that are selected by the mask 0x7ff0000000000000L)
represent the exponent. Bits 51-0 (the bits that are selected by the mask 0x000fffffffffffffL)
represent the significand (sometimes called the mantissa) of the floating-point number.
If the argument is positive infinity, the result is 0x7ff0000000000000L.
If the argument is negative infinity, the result is 0xfff0000000000000L.
If the argument is NaN, the result is 0x7ff8000000000000L.
In all cases, the result is a long integer that, when given to the longBitsToDouble(long) method,
will produce a floating-point value equal to the argument to doubleToLongBits().
doubleValue
public double doubleValue()
- Returns the double value of this Double.
equals
public boolean equals(Object obj)
- Compares this object against the specified object. The result is true if and only if the argument
is not null and is a Double object that represents a double that has the identical bit pattern to the
bit pattern of the double represented by this object. For this purpose, two double values are
considered to be the same if and only if the method doubleToLongBits(double) returns the same
long value when applied to each.
Note that in most cases, for two instances of class Double, d1 and d2, the value of
d1.equals(d2) is true if and only if d1.doubleValue() == d2.doubleValue() also has the value true.
However, there are two exceptions:
If d1 and d2 both represent Double.NaN, then the equals method returns true,
even though Double.NaN==Double.NaN has the value false.
If d1 represents +0.0 while d2 represents -0.0, or vice versa, the equals test has the value false,
even though +0.0==-0.0 has the value true. This allows hashtables to operate properly.
- Overrides:
equals in class Object
- Parameters:
obj - the reference object with which to compare.
- Returns:
- true if this object is the same as the obj argument; false otherwise.
floatValue
public float floatValue()
- Returns the float value of this Double.
hashCode
public int hashCode()
- Returns a hashcode for this Double object. The result is the exclusive
OR of the two halves of the long integer bit representation, exactly
as produced by the method doubleToLongBits(double), of the primitive
double value represented by this Double object. That is, the hashcode
is the value of the expression:
(int)(v^(v>>>32))
where v is defined by:
long v = Double.doubleToLongBits(this.doubleValue());
- Overrides:
hashCode in class Object
intValue
public int intValue()
- Returns the integer value of this Double (by casting to an int).
isInfinite
public boolean isInfinite()
- Returns true if this Double value is infinitely large in magnitude.
isInfinite
public static boolean isInfinite(double v)
- Returns true if this Double value is infinitely large in magnitude.
isNaN
public boolean isNaN()
- Returns true if this Double value is the special Not-a-Number (NaN) value.
isNaN
public static boolean isNaN(double v)
- Returns true if the specified number is the special Not-a-Number (NaN) value.
longBitsToDouble
public static double longBitsToDouble(long bits)
- Returns the double-float corresponding to a given bit representation. The argument is considered
to be a representation of a floating-point value according to the IEEE 754 floating-point
"double precision" bit layout. That floating-point value is returned as the result.
If the argument is 0x7ff0000000000000L, the result is positive infinity.
If the argument is 0xfff0000000000000L, the result is negative infinity.
If the argument is any value in the range 0x7ff0000000000001L through 0x7fffffffffffffffL or
in the range 0xfff0000000000001L through 0xffffffffffffffffL, the result is NaN.
All IEEE 754 NaN values of type double are, in effect, lumped together by the
Java programming language into a single value called NaN.
In all other cases, let s, e, and m be three values that can be computed from the argument:
int s = ((bits >> 63) == 0) ? 1 : -1;
int e = (int)((bits >> 52) & 0x7ffL);
long m = (e == 0) ?
(bits & 0xfffffffffffffL) << 1 :
(bits & 0xfffffffffffffL) | 0x10000000000000L;
Then the floating-point result equals the value of the mathematical expression s?m?2e-1075
longValue
public long longValue()
- Returns the long value of this Double (by casting to a long).
parseDouble
public static double parseDouble(String s)
throws NumberFormatException
- Returns a new double initialized to the value represented by the
specified String, as performed by the valueOf method of class Double.
- Throws:
NumberFormatException
shortValue
public short shortValue()
- Returns the value of this Double as a short (by casting to a short).
toString
public String toString()
- Returns a String representation of this Double object. The primitive
double value represented by this object is converted to a string exactly
as if by the method toString of one argument.
- Overrides:
toString in class Object
toString
public static String toString(double f)
- Creates a string representation of the double argument. All characters mentioned below are
ASCII characters.
If the argument is NaN, the result is the string "NaN".
Otherwise, the result is a string that represents the sign and magnitude (absolute value)
of the argument.
If the sign is negative, the first character of the result is '-' ('-');
if the sign is positive, no sign character appears in the result. As for the magnitude m:
If m is infinity, it is represented by the characters "Infinity"; thus, positive infinity produces
the result "Infinity" and negative infinity produces the result "-Infinity".
If m is zero, it is represented by the characters "0.0"; thus, negative zero produces the result
"-0.0" and positive zero produces the result "0.0".
If m is greater than or equal to 10-3 but less than 107, then it is represented as the integer part
of m, in decimal form with no leading zeroes, followed by '.' (.), followed by one or more decimal digits representing the fractional part of m.
If m is less than 10-3 or not less than 107, then it is represented in so-called "computerized
scientific notation." Let n be the unique integer such that 10n<=m<10n+1; then let a be the mathematically exact quotient of m and 10n so that 1<=a<10.
The magnitude is then represented as the integer part of a, as a single decimal digit, followed by
'.' (.), followed by decimal digits representing the fractional part of a, followed by the letter
'E' (E), followed by a representation of n as a decimal integer, as produced by the method Integer.toString(int).
How many digits must be printed for the fractional part of m or a? There must be at least one digit
to represent the fractional part, and beyond that as many, but only as many, more digits as are needed
to uniquely distinguish the argument value from adjacent values of type double. That is, suppose that
x is the exact mathematical value represented by the decimal representation produced by this method
for a finite nonzero argument d. Then d must be the double value nearest to x; or if two double
values are equally close to x, then d must be one of them and the least significant bit of the
significand of d must be 0.
valueOf
public static Double valueOf(String s)
throws NumberFormatException
- Returns a new Double object initialized to the value represented by the specified string.
The string s is interpreted as the representation of a floating-point value and a Double object
representing that value is created and returned.
If s is null, then a NullPointerException is thrown.
Leading and trailing whitespace characters in s are ignored. The rest of s should constitute a
FloatValue as described by the lexical rule:
FloatValue:
Signopt FloatingPointLiteral
where Sign and FloatingPointLiteral are as defined in Section 3.10.2 of the Java Language Specification.
If it does not have the form of a FloatValue, then a NumberFormatException is thrown. Otherwise, it is
regarded as representing an exact decimal value in the usual "computerized scientific notation"; this exact
decimal value is then conceptually converted to an "infinitely precise" binary value that is then rounded to
type double by the usual round-to-nearest rule of IEEE 754 floating-point arithmetic. Finally, a new object
of class Double is created to represent the double value.
- Throws:
NumberFormatException